Consider a beryllium (Z = 4)ion with all but one of its electrons removed.What is the kinetic energy of the electron in the n = 1 orbit.(The radius of the 1st Bohr orbit in Be³⁺ is 0.0132 nm.) A)54.4 eV B)218 eV C)13.6 eV D)27.2 eV E)109 eV

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Quizplus · Accepted Answer

The kinetic energy of an electron in a hydrogen-like ion is given by $ KE = \frac{13.6 \times Z^2}{n^2} $ eV. For Be$^{3+}$, Z = 4 and n = 1, so $ KE = \frac{13.6 \times 4^2}{1^2} = 218 $ eV.

Consider a Beryllium (Z = 4)ion with All but One