The resistivity of nichrome at 20ºC is 100 $\times$ 10^-8 $\Omega$ · m.You have nichrome wire whose diameter is 2.50 mm and need a resistance of 100 $\Omega$.How long would a piece of this wire need to be to provide this resistance? A)196 m B)491 m C)543 m D)867 m E)1.96 km

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Quizplus · Accepted Answer

To find the length of the wire, use the formula for resistance: R = ρ(L/A), where R is resistance, ρ is resistivity, L is length, and A is the cross-sectional area. The area A = π(d/2)^2, where d is the diameter. Solving for L gives L = R * A / ρ. Substituting the given values, L = 100 * π(0.0025/2)^2 / (100 x 10^-8) = 491 m.

The Resistivity of Nichrome at 20ºC Is 100 ×\times× 10-8 Ω\OmegaΩ · MYou Have Nichrome Wire Whose Diameter Is 2

The Resistivity of Nichrome at 20ºC Is 100 $\times$ 10^-8 $\Omega$ · MYou Have Nichrome Wire Whose Diameter Is 2