The distance to a particular galaxy is 60 million light years.If you assume Hubble's constant to be 23 km/s/10⁶ c · y,then what redshift recession velocity would you expect to measure? A)zero B)1.4 $\times$ 10³ km/s C)2.6 $\times$ 10³ km/s D)0.38 $\times$ 10³ km/s E)None of these is correct.

Question

Quizplus · Accepted Answer

The recession velocity can be calculated using Hubble's Law: $v = H_0 \times d$, where $H_0$ is Hubble's constant (23 km/s/Mpc) and $d$ is the distance to the galaxy in megaparsecs (Mpc). First, convert the distance from light years to Mpc: $60 \times 10^6$ light years $= 60 \times 10^6 / 3.26 = 18.4$ Mpc. Then, calculate the recession velocity: $v = 23 \times 18.4 = 423.2$ km/s, which is closest to the option $1.4 \times 10^{3}$ km/s.

The Distance to a Particular Galaxy Is 60 Million Light ×\times×

The Distance to a Particular Galaxy Is 60 Million Light $\times$