The solution of $x y ^ { \prime } = ( x + 1 ) y ^ { 2 }$
A) $y = 1 / ( x + \ln x + c )$
B) $y = 1 / ( x - \ln x + c )$
C) $y = - c / ( x + \ln x )$
D) $y = - c / ( x - \ln x )$
E) $y = - 1 / ( x + \ln x + c )$

Name: The solution of $x y ^ { \prime } = ( x + 1 ) y ^ { 2 }$ A) $y = 1 / ( x + \ln x + c )$ B) $y = 1 / ( x - \ln x + c )$ C) $y = - c / ( x + \ln x )$ D) $y = - c / ( x - \ln x )$ E) $y = - 1 / ( x + \ln x + c )$
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The Answer is E

The Solution Of xy′=(x+1)y2x y ^ { \prime } = ( x + 1 ) y ^ { 2 }xy′=(x+1)y2

The Solution Of $x y ^ { \prime } = ( x + 1 ) y ^ { 2 }$