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The Solution Of y4y+13y=0y ^ { \prime \prime } - 4 y ^ { \prime } + 13 y = 0

Question 1

Multiple Choice

The solution of y4y+13y=0y ^ { \prime \prime } - 4 y ^ { \prime } + 13 y = 0 is


A) y=c1e2xcos(3x) +c2e2xsin(3x) y = c _ { 1 } e ^ { - 2 x } \cos ( 3 x ) + c _ { 2 } e ^ { - 2 x } \sin ( 3 x )
B) y=c1e2xcos(3x) +c2e2xsin(3x) y = c _ { 1 } e ^ { - 2 x } \cos ( 3 x ) + c _ { 2 } e ^ { 2 x } \sin ( 3 x )
C) y=c1e2xcos(3x) +c2e2xsin(3x) y = c _ { 1 } e ^ { 2 x } \cos ( 3 x ) + c _ { 2 } e ^ { 2 x } \sin ( 3 x )
D) y=c1e2x+c2e3xy = c _ { 1 } e ^ { 2 x } + c _ { 2 } e ^ { 3 x }
E) y=c1cos(3x) +c2sin(3x) y = c _ { 1 } \cos ( 3 x ) + c _ { 2 } \sin ( 3 x )

Correct Answer:

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