When a hydrogen atom absorbs a photon with E = 4.089 $\times$ 10^-19 J, what is the frequency of the photon? A) 6.17 $\times$ 10¹⁴ Hz B) 2.45 $\times$ 10¹⁸ Hz C) 2.55 $\times$ 10⁸ Hz D) 6.623 $\times$ 10³⁴ Hz E) None of these is correct.

Question

Quizplus · Accepted Answer

The frequency of the photon can be calculated using the formula E = hν, where E is the energy of the photon, h is Planck's constant, and ν is the frequency of the photon. Rearranging the formula, we get ν = E/h. Plugging in the values, we get:

ν = (4.089 x 10^11 J)/(6.626 x 10^-34 J s)
ν ≈ 6.17 x 10^20 Hz

Converting the answer to scientific notation in the format given, we get answer choice A).

When a Hydrogen Atom Absorbs a Photon with E = ×\times×

When a Hydrogen Atom Absorbs a Photon with E = $\times$