A string whose length is 1 m is fixed at both ends and vibrates according to the equation
Y(x, t) = 0.04 sin $\pi$x cos 2$\pi$t
Where the units are SI. The total number of nodes exhibited by the string is
A) 1
B) 2
C) 3
D) 4
E) 5

Question

Quizplus · Accepted Answer

The equation for the standing wave on a string fixed at both ends is given by Y(x, t) = 2A sin(nπx/L) cos(wt), where n is the number of nodes. Comparing this with the given equation, we can see that F1F1F1S1 is the harmonic number, which is equal to n. Thus, we have n=2, which corresponds to two nodes on the string. Therefore, the answer is B.

A String Whose Length Is 1 M Is Fixed at Both