If a mass of oxygen gas occupies a volume of 8 L at standard temperature and pressure,what is the change in the volume if the temperature is decreased to 136 K and the pressure remains constant?
A)It increases to 16 L.
B)It decreases to 12 L.
C)It increases to 24 L.
D)It decreases to 4 L.
E)It increases to 12 L.

Question

Quizplus · Accepted Answer

The volume of a gas is directly proportional to the temperature if the pressure is constant. Therefore, if the temperature is decreased, the volume will also decrease. We can use the following formula:

V1/T1 = V2/T2

where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature, respectively.

Plugging in the given values, we get:

8 L / 273 K = V2 / 136 K

Solving for V2, we get:

V2 = (8 L / 273 K) * 136 K = 2.35 L

Therefore, the change in volume is:

8 L - 2.35 L = 5.65 L

So, the final volume is:

8 L - 5.65 L = 2.35 L

which is less than the initial volume of 8 L. The closest answer choice is (D), which predicts that the volume decreases to 4 L.

If a Mass of Oxygen Gas Occupies a Volume of 8