Indicate which products would be obtained from the chlorination of 1,5-hexadiene at high temperature (500 $\circ$ C),using a 1:1 mole ratio of the reactants.
A)I and II
B)II and III
C)III and IV
D)IV and V
E)V and I

Question

Indicate which products would be obtained from the chlorination of 1,5-hexadiene at high temperature (500 $\circ$ C),using a 1:1 mole ratio of the reactants. 
A)I and II 
B)II and III 
C)III and IV 
D)IV and V 
E)V and I

Quizplus · Accepted Answer

Chlorination of 1,5-hexadiene at high temperature with a 1:1 mole ratio of reactants would result in the formation of four possible products: 1,5-dichlorohexane (I), 1,2-dichlorohexane (II), 1,4-dichlorohexane (III), and 1,6-dichlorohexane (IV). Since the reactants are in a 1:1 mole ratio, only one of the double bonds in 1,5-hexadiene will react with a single chlorine atom. This means that products I and IV are not possible, as they would require both double bonds to react.

Product II (1,2-dichlorohexane) can be obtained by reacting one chlorine atom with the double bond closest to the terminal methyl group, while product III (1,4-dichlorohexane) can be obtained by reacting one chlorine atom with the double bond closest to the central methyl group. Therefore, the only possible products from the chlorination of 1,5-hexadiene at high temperature with a 1:1 mole ratio of reactants are II and III (Choice C).

Indicate Which Products Would Be Obtained from the Chlorination of 1,5-Hexadiene