What volume (mL)of a 15% (m/v)NaOH solution contains 120 g NaOH? A)18 mL B)0.13 mL C)13 mL D)120 mL E)8.0 × 10² mL

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Quizplus · Accepted Answer

To find the volume of the solution that contains 120 g of NaOH in a 15% (m/v) solution, we use the formula: $\text{mass (g)} = \text{volume (mL)} \times \text{concentration (% m/v)}$. Rearranging to solve for volume gives: $\text{volume (mL)} = \frac{\text{mass (g)}}{\text{concentration (% m/v)}}$. Plugging in the given values: $\text{volume (mL)} = \frac{120 \text{ g}}{15\%} = \frac{120}{0.15} = 800 \text{ mL}$, which is equivalent to $8.0 \times 10^2 \text{ mL}$.

What Volume (ML)of a 15% (M/v)NaOH Solution Contains 120 G