What volume of a 2.00 M KCl solution is required to prepare 500.mL of a 0.100 M KCl solution? A)0.0400 mL B)25.0 mL C)2.00 mL D)1.00 × 10⁴ mL E)5.00 × 10² mL

Question

Quizplus · Accepted Answer

We can use the formula:
M1V1 = M2V2
where,
M1 = 2.00 M (initial concentration)
V1 = volume of initial solution to be taken
M2 = 0.100 M (final concentration)
V2 = 500. mL (final volume required)

Substituting the values, we get:
2.00 M V1 = 0.100 M (500. mL)
V1 = (0.100 M × 500. mL) ÷ 2.00 M
V1 = 25.0 mL

Therefore, we need to take 25.0 mL of the 2.00 M KCl solution and dilute it to 500. mL to obtain a 0.100 M KCl solution. Hence, the best choice is B) 25.0 mL.

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