What is the new mass/volume percent (m/v)of a KOH solution that is prepared by diluting 110 mL of a 6.0% (m/v)KOH solution to 330 mL?
A)2.0% (m/v)
B)1.0% (m/v)
C)6.0% (m/v)
D)12% (m/v)
E)18% (m/v)

Question

Quizplus · Accepted Answer

To find the new mass/volume percent (m/v) of the diluted solution, we need to use the formula:

(mass/volume)1 x volume1 = (mass/volume)2 x volume2

where:
(mass/volume)1 = initial mass/volume percent of KOH solution (6.0%)
volume1 = initial volume of KOH solution (110 mL)
(mass/volume)2 = final mass/volume percent of KOH solution (unknown)
volume2 = final volume of KOH solution (330 mL)

Solving for (mass/volume)2:

(6.0%) x (110 mL) = (mass/volume)2 x (330 mL)
mass/volume = (6.0% x 110 mL) / 330 mL
mass/volume = 1.8%

Therefore, the new mass/volume percent (m/v) of the KOH solution after dilution is 1.8%, which is closest to answer choice A) 2.0% (m/v).

What Is the New Mass/volume Percent (M/v)of a KOH Solution