For the following question(s),consider the following equation. 2Mg + O 2 → 2MgO -In the reaction of silver nitrate with sodium chloride,how many grams of silver chloride will be produced from 100.g of silver nitrate when it is mixed with an excess of sodium chloride? The equation for the reaction is below. AgNO₃ + NaCl → AgCl + NaNO₃ A)107.9 g B)169.9 g C)84.4 g D)0.589 g E)58.9 g

Question

Quizplus · Accepted Answer

To determine the amount of silver chloride produced, we need to use stoichiometry and the molar ratios of the reactants and products.

1. Convert 100 g of AgNO3 to moles:
100 g AgNO3 x (1 mol AgNO3/169.87 g AgNO3) = 0.589 mol AgNO3

2. Use the balanced equation to determine the moles of AgCl produced:
1 mol AgNO3 produces 1 mol AgCl
0.589 mol AgNO3 x (1 mol AgCl/1 mol AgNO3) = 0.589 mol AgCl

3. Convert moles of AgCl to grams:
0.589 mol AgCl x (143.32 g AgCl/mol AgCl) = 84.4 g AgCl

Therefore, 100 g of AgNO3 will produce 84.4 g of AgCl. The correct answer is C.

For the Following Question(s),consider the Following Equation