Barium chloride and sodium sulfate react according to the following equation.
BaCl2 + Na2SO4 → BaSO4 + 2NaCl
Answer the following question(s)about this reaction.
-How many grams of barium chloride are needed to make 100.grams of barium sulfate?
A)44.9 g
B)89.2 g
C)208 g
D)233 g
E)46.6 g

Question

Barium chloride and sodium sulfate react according to the following equation.
BaCl2 + Na2SO4 → BaSO4 + 2NaCl 
Answer the following question(s)about this reaction.
-How many grams of barium chloride are needed to make 100.grams of barium sulfate?
A)44.9 g
B)89.2 g
C)208 g
D)233 g
E)46.6 g

Quizplus · Accepted Answer

The molar mass of BaSO4 is approximately 233 g/mol, and the molar mass of BaCl2 is approximately 208 g/mol. To produce 100 g of BaSO4, you need (100 g / 233 g/mol) = 0.429 moles of BaSO4. Since the reaction is 1:1, you need 0.429 moles of BaCl2, which is 0.429 moles * 208 g/mol = 89.2 g of BaCl2.

Barium Chloride and Sodium Sulfate React According to the Following