A point on the rim of a 0.25-m-radius fan blade has centripetal acceleration of 0.20 m/s².Find the centripetal acceleration of a point 0.05 m from the center of the same wheel. A)0.01 m/s² B)0.02 m/s² C)0.04 m/s² D)0.08 m/s²

Question

Quizplus · Accepted Answer

Centripetal acceleration is given by a = v^2/r, where v is the tangential velocity and r is the distance from the center of rotation.

For the point on the rim of the fan blade, we are given a = 0.20 m/s^2 and r = 0.25 m. We can solve for v using the formula a = v^2/r:

0.20 m/s^2 = v^2 / 0.25 m

v^2 = 0.05 m^2/s^2

v = sqrt(0.05) m/s

Now, we can use the same formula to find the centripetal acceleration of a point 0.05 m from the center:

a = v^2 / r = (sqrt(0.05))^2 / 0.05 = 0.04 m/s^2

Therefore, the answer is C.

A Point on the Rim of a 0