A man pulls a sled at a constant velocity across a horizontal snow surface.If a force of 80 N is being applied to the sled rope at an angle of 53 $\degree$to the ground,what is the force of friction between sled and snow?
A)80 N
B)64 N
C)48 N
D)40 N

Question

Quizplus · Accepted Answer

Since the sled is moving at a constant velocity in a horizontal direction, the applied force must be equal and opposite to the force of friction acting on it. Therefore, the force of friction can be calculated as follows:

The force component acting along the horizontal direction can be found by multiplying the applied force with the cosine of the angle between the rope and the ground.

F_horizontal = 80 cos(53°) = 50.3 N

Since there is no acceleration, the force of friction must be equal to F_horizontal.

Therefore, the force of friction = 50.3 N ~ 48 N (rounded to the nearest whole number).

Hence, the correct answer is C) 48 N.

A Man Pulls a Sled at a Constant Velocity Across °\degree°

A Man Pulls a Sled at a Constant Velocity Across $\degree$