A hockey puck moving at 7.0 m/s coasts to a halt in 75 m on a smooth ice surface.What is the coefficient of friction between the ice and the puck?
A)m = 0.025
B)m = 0.033
C)m = 0.12
D)m = 0.25

Question

Quizplus · Accepted Answer

The coefficient of friction can be found using the formula: $ \mu = \frac{v^2}{2gd} $, where $ v $ is the initial velocity, $ g $ is the acceleration due to gravity (9.8 m/s²), and $ d $ is the distance. Plugging in the values: $ \mu = \frac{7^2}{2 \times 9.8 \times 75} \approx 0.033 $.

A Hockey Puck Moving at 7