A circular loop carrying a current of 1.0 A is oriented in a magnetic field of 0.35 T.The loop has an area of 0.24 m² and is mounted on an axis,perpendicular to the magnetic field,which allows the loop to rotate.If the plane of the loop is oriented parallel to the field,what torque is created by the interaction of the loop current and the field?

Question

Quizplus · Accepted Answer

The torque created by the interaction of the loop current and the magnetic field is given by the equation τ = NIABsinθ, where N is the number of turns in the loop (which is one in this case), I is the current, A is the area of the loop, B is the magnitude of the magnetic field, and θ is the angle between the normal to the plane of the loop and the direction of the magnetic field. 
Since the plane of the loop is oriented parallel to the field, θ = 0, and sinθ = 0. Therefore, the torque is zero.

A Circular Loop Carrying a Current of 1