The dielectric strength of Rutile is 6.0 x 10⁶ V/m,which corresponds to the maximum electric field that the dielectric can sustain before breakdown.What is the maximum charge that a 10^-10-F capacitor with a 1.0-mm thickness of Rutile can hold? A)1.7 nC B)0.60 µC C)0.30 mC D)6.0 C

Question

Quizplus · Accepted Answer

The maximum charge that the capacitor can hold can be calculated by using the formula:

Q = εrε0A V

where
εr is the relative permittivity of Rutile,
ε0 is the vacuum permittivity,
A is the area of the capacitor plates, and
V is the voltage across the capacitor.

The thickness of the Rutile is not required to find the maximum charge.

Rearranging the formula and substituting the given values, we get:

V = dielectric strength of Rutile = 6.0 × 10^6 V/m
εr = 104
ε0 = 8.85 × 10^-12 F/m
A = (10^-3 m)^2 = 10^-6 m^2

Q = (104 × 8.85 × 10^-12 × 10^-6 × 6.0 × 10^6) C
Q = 0.60 µC

Therefore, the maximum charge that the capacitor can hold is 0.60 µC or choice B.

The Dielectric Strength of Rutile Is 6