A parallel plate capacitor with plate separation d has capacitance .The gap between its plates is then partially filled with a dielectric with dielectric constant and having a thickness d/3.What is the resulting capacitance?

Question

A parallel plate capacitor with plate separation d has capacitance  .The gap between its plates is then partially filled with a dielectric with dielectric constant  and having a thickness d/3.What is the resulting capacitance?

Quizplus · Accepted Answer

The capacitance of a capacitor is given by C=εA/d where ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between them.

Initially, the capacitance is C = 11eaa64f_9009_30a3_a696_1b7599716875_TB5258_11.

When the dielectric is partially introduced, the capacitance becomes C' = κεA/(d/3 + 2d/3) = (3κ/4)C, where κ is the dielectric constant of the material.

Substituting the given values, we get C' = 11eaa64f_9009_7ec6_a696_d16923a51869_TB5258_11, which is option B.

A Parallel Plate Capacitor with Plate Separation D Has Capacitance