The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.160 m)cos (pt/16).What is its period of oscillation?
A)100 s
B)32 s
C)16 s
D)8.0 s

Name: The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.160 m)cos (pt/16).What is its period of oscillation? A)100 s B)32 s C)16 s D)8.0 s
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Question

Quizplus · Accepted Answer

The period T of a simple harmonic motion described by x = A cos(ωt) is given by T = 2π/ω. Here, ω = π/16, so T = 2π/(π/16) = 32 s.

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