The position of a 0.64-kg mass undergoing simple harmonic motion is given by x = (0.160 m)cos (pt/16).What is the maximum net force on the mass as it oscillates? A)3.9 ´ 10^-3 N B)9.9 ´ 10^-3 N C)1.3 ´ 10^-3 N D)6.3 N

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Quizplus · Accepted Answer

The maximum net force on the mass is equal to the maximum value of the restoring force, which is given by F = kx, where k is the spring constant and x is the maximum displacement. In this case, k = mω^2 = (0.64 kg)(π/16 s)^2 = 0.64 N/m and x = 0.160 m, so the maximum net force is F = kx = (0.64 N/m)(0.160 m) = 0.1024 N.

The Position of a 0