I take 1.0 kg of ice and dump it into 1.0 kg of water and,when equilibrium is reached,I have 2.0 kg of ice at 0 C.The water was originally at 0 C.The specific heat of water = 1.00 kcal/kg* C,the specific heat of ice = 0.50 kcal/kg* C,and the latent heat of fusion of water is 80 kcal/kg.The original temperature of the ice was:
A) one or two degrees below 0 C.
B) -80 C.
C) -160 C.
D) The whole experiment is impossible.
Correct Answer:
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