The produce manager at a local Sobeys store is interested in estimating the percentage of apples that arrive on a shipment with bruises. A random sample of 150 apples showed 14 with bruises. Based on this information, what is the margin of error for a 95% confidence interval estimate?
A) 0.0466
B) 0.0933
C) 0.0006
D) 0.0238
E) 0.0392

Question

Quizplus · Accepted Answer

The margin of error for a proportion is calculated using the formula: ME = Z * sqrt[(p(1-p))/n], where Z is the Z-score for a 95% confidence level (1.96), p is the sample proportion (14/150), and n is the sample size (150). Calculating this gives approximately 0.0466.

The Produce Manager at a Local Sobeys Store Is Interested