Naphthalene Undergoes Sublimation: C₁₀H₈(s) $\leftrightarrows$ C₁₀H₈(g) $\times$ 10^-3
B)K_p = 1 $\times$ 10^-4; K_c = 1

Naphthalene undergoes sublimation: C₁₀H₈(s) $\leftrightarrows$ C₁₀H₈(g) .In a closed container at 300.0 K,the equilibrium vapor pressure is 0.10 torr.What are the values of K_p and K_c?

A) K_p = 0.10; K_c = 4.1 $\times$ 10^-3
B) K_p = 1.3 $\times$ 10^-4; K_c = 1.3 $\times$ 10^-4
C) K_p = 1.3 $\times$ 10^-4; K_c = 3.2 $\times$ 10^-3
D) K_p = 1.3 $\times$ 10^-4; K_c = 5.3 $\times$ 10^-6
E) More information is required.