Calculate the maximum amount of work that can be done by the reaction CH₄(g)+ 2 O₂(g)$\leftrightarrows$CO₂(g)+ 2 H₂O(g),given

Question

Quizplus · Accepted Answer

First, we need to balance the equation:

CH4(g) + 2O2(g) -> CO2(g) + 2H2O(g)

Now, we can use the given enthalpy values to calculate the maximum amount of work:

ΔH = ΣnΔHf(products) - ΣnΔHf(reactants)

= (1 mol CO2)(-393.5 kJ/mol) + (2 mol H2O)(-285.8 kJ/mol) - (1 mol CH4)(-74.8 kJ/mol) - (2 mol O2)(0 kJ/mol)

= -802.3 kJ/mol

Since we want the maximum amount of work, we need to take the absolute value of ΔH:

|-802.3 kJ/mol| = 802.3 kJ/mol

Therefore, the correct answer is (C) -902.3 kJ/mol (the negative sign indicates that the reaction is exothermic, and the absolute value indicates the maximum amount of work that can be done).

Calculate the Maximum Amount of Work That Can Be Done ⇆\leftrightarrows⇆

Calculate the Maximum Amount of Work That Can Be Done $\leftrightarrows$