A solution is prepared by mixing 50.00 g of methanol (CH₃OH,32.04 g/mol)with 50.00 g of ethanol (CH₃CH₂OH,46.07 g/mol).Use the following data to determine the vapor pressure of this solution at 20 $\circ$ C.

Question

Quizplus · Accepted Answer

The vapor pressure of the solution is calculated using Raoult's Law. First, calculate the mole fraction of each component. Methanol: 50.00 g / 32.04 g/mol = 1.56 mol. Ethanol: 50.00 g / 46.07 g/mol = 1.09 mol. Total moles = 1.56 + 1.09 = 2.65 mol. Mole fraction of methanol = 1.56 / 2.65 = 0.589. Mole fraction of ethanol = 1.09 / 2.65 = 0.411. Vapor pressure of solution = (0.589 * 92 torr) + (0.411 * 45 torr) = 73 torr.

A Solution Is Prepared by Mixing 50 ∘\circ∘ C A)69 Torr B)57 Torr C)79 Torr D)73

A Solution Is Prepared by Mixing 50 $\circ$ C

A)69 Torr
B)57 Torr
C)79 Torr
D)73