You wish to prepare a solution of methanol (CH₃OH,32.04 g/mol)and ethanol (CH₃CH₂OH,46.07 g/mol)that has a total vapor pressure of 66 torr at 20 $\circ$ C.Calculate the mole fraction of ethanol in the solution that will produce the desired pressure.

Question

Quizplus · Accepted Answer

The mole fraction of ethanol in the solution can be calculated using Raoult's law:Ptotal = P1*X1 + P2*X2where Ptotal is the total vapor pressure, P1 and P2 are the vapor pressures of the pure components, and X1 and X2 are the mole fractions of the components.Substituting the given values into the equation, we get:66 torr = 92 torr*X1 + 45 torr*X2Solving for X2, we get:X2 = (66 torr - 92 torr*X1) / 45 torrSince the mole fraction of methanol is X1 = 1 - X2, we can substitute this into the equation and solve for X2:X2 = (66 torr - 92 torr*(1 - X2)) / 45 torrX2 = 0.68Therefore, the mole fraction of ethanol in the solution that will produce the desired pressure is 0.68.

You Wish to Prepare a Solution of Methanol (CH3OH,32 ∘\circ∘ CCalculate the Mole Fraction of Ethanol in the Solution That

You Wish to Prepare a Solution of Methanol (CH₃OH,32 $\circ$ CCalculate the Mole Fraction of Ethanol in the Solution That