How many moles of solute are there in a 0.155 m glucose (C₆H₁₂O₆)solution prepared with 50.0 kg of water?

Question

Quizplus · Accepted Answer

To solve for the number of moles of solute in a given solution, we can use the formula:

moles of solute = concentration (in mol/L) x volume (in L)

However, in this case, we are given the concentration in units of molarity (mol/L) and the volume in units of mass (kg). To convert from mass to volume, we need to use the density of the solution, which is typically given in units of g/mL or kg/L.

We can first convert the mass of water given (50.0 kg) to volume using the density of water (1 g/mL or 1000 kg/L):

50.0 kg x (1000 g / 1 kg) x (1 L / 1000 mL) = 50 L

Next, we can use the molarity given (0.155 m) to calculate the number of moles of solute:

0.155 mol/L x 50 L = 7.75 mol

Therefore, the answer is (E) 7.75 mol.

How Many Moles of Solute Are There in a 0