Hydrogen sulfide gas (H₂S,34.08 g/mol)can be produced from the reaction of aluminum sulfide (150.2 g/mol)and water (18.02 g/mol)according to the following reaction equation: Al₂S₃(s)+ 6 H₂O( )$\to$ 3 H₂S(g)+ 2 Al(OH)₃(s) If 65.0 g Al₂S₃ reacts with excess H₂O at 90.0 $\circ$ C and 0.987 atm,what volume of H₂S gas will be produced?

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The Answer of Hydrogen sulfide gas (H₂S,34.08 g/mol)can be produced from the reaction of aluminum sulfide (150.2 g/mol)and water (18.02 g/mol)according to the following reaction equation: Al₂S₃(s)+ 6 H₂O( )$\to$ 3 H₂S(g)+ 2 Al(OH)₃(s) If 65.0 g Al₂S₃ reacts with excess H₂O at 90.0 $\circ$ C and 0.987 atm,what volume of H₂S gas will be produced?

Hydrogen Sulfide Gas (H2S,34 →\to→ 3 H2S(g)+ 2 Al(OH)3(s) If 65 ∘\circ∘

Hydrogen Sulfide Gas (H₂S,34 $\to$ 3 H₂S(g)+ 2 Al(OH)₃(s)
If 65 $\circ$