The freezing point of ammonia (NH₃,17.04 g/mol)is -77.73°C.In an experiment,367.2 grams of solid NH₃ at -77.73°C is used to cool 250.0 grams of liquid NH₃ from 25.00°C to the freezing point.Assume that the specific heat capacity of liquid NH₃ is 4.742 J/(g.°C).What is the enthalpy of fusion of ammonia?

Question

Quizplus · Accepted Answer

The enthalpy of fusion can be calculated using the heat lost by the liquid ammonia as it cools to the freezing point. The heat lost is equal to the mass of the liquid ammonia multiplied by its specific heat capacity and the temperature change. This heat is absorbed by the solid ammonia to melt, and using the mass of solid ammonia and its molar mass, the enthalpy of fusion can be calculated.

The Freezing Point of Ammonia (NH3,17

The Freezing Point of Ammonia (NH₃,17