Quicklime,CaO,can be produced by heating calcium hydroxide,Ca(OH)₂.What is the percent yield if 45 grams of quicklime are obtained from 1 mole of calcium hydroxide?

Question

Quizplus · Accepted Answer

To determine the percent yield, we need to compare the actual yield (45 g) to the theoretical yield of CaO that can be produced from 1 mole of Ca(OH)2.

The balanced equation for the reaction is:
Ca(OH)2 → CaO + H2O

The molar mass of Ca(OH)2 is 74.1 g/mol, and that of CaO is 56.1 g/mol. 
So, 1 mole of Ca(OH)2 produces 1 mole of CaO.

From 1 mole of Ca(OH)2, the theoretical yield of CaO is:
56.1 g/mol x 1 mol = 56.1 g

The percent yield is:
(Actual yield / Theoretical yield) x 100%

= (45 g / 56.1 g) x 100%

= 80%

Therefore, the answer is (B) 80%.

Quicklime,CaO,can Be Produced by Heating Calcium Hydroxide,Ca(OH)2

Quicklime,CaO,can Be Produced by Heating Calcium Hydroxide,Ca(OH)₂