Acrylonitrile (53.07 g/mol)can be produced from propylene (42.09 g/mol)according to the reaction shown below.If the percent yield of the reaction is only 45.7%,how many grams of C₃H₆ should be used if 1250 g C₃H₃N must actually be produced? 4 C₃H₆(g)+ 6 NO(g)$\to$ 4 C₃H₃N + 6 H₂O + N₂(g)

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The Answer of Acrylonitrile (53.07 g/mol)can be produced from propylene (42.09 g/mol)according to the reaction shown below.If the percent yield of the reaction is only 45.7%,how many grams of C₃H₆ should be used if 1250 g C₃H₃N must actually be produced? 4 C₃H₆(g)+ 6 NO(g)$\to$ 4 C₃H₃N + 6 H₂O + N₂(g)

Acrylonitrile (53 →\to→ 4 C3H3N + 6 H2O + N2(g)

Acrylonitrile (53 $\to$ 4 C₃H₃N + 6 H₂O + N₂(g)