The combustion of hydrogen gas releases 286 kJ per mol of hydrogen.If 13.0 L of hydrogen at STP was burned to produce electricity,how long would it power a 100-watt (W)light bulb? Assume no energy is lost to the surroundings.(1 W = 1 J/s)

Question

Quizplus · Accepted Answer

The combustion of 1 mol of hydrogen releases 286 kJ of energy. 13.0 L of hydrogen at STP is 13.0 L / 22.4 L/mol = 0.58 mol of hydrogen. The energy released by burning 0.58 mol of hydrogen is 0.58 mol * 286 kJ/mol = 166 kJ. A 100-watt light bulb uses 100 J of energy per second. The time that 166 kJ of energy can power a 100-watt light bulb is 166 kJ / 100 J/s = 1660 s = 27.7 min.

The Combustion of Hydrogen Gas Releases 286 KJ Per Mol