What volume does 40.5 g of N₂ occupy at STP?

Question

Quizplus · Accepted Answer

According to the ideal gas law, PV=nRT, we can obtain the volume of a gas at STP using V=nRT/P, where n is the number of moles of the gas, R is the gas constant, T is the temperature in Kelvin (273.15 K at STP), and P is the pressure (1 atm at STP). To find n, we need to convert the mass of N₂ given to moles using its molar mass. The molar mass of N₂ is approximately 263.1 g/mol (since it is not a real compound, the molar mass is estimated). Therefore, the number of moles of N₂ in 40.5 g is 0.154 mol. Plugging this value along with the other constants into the equation for V, we get V=(0.154 mol)(0.08206 L atm mol^-1 K^-1)(273.15 K)/(1 atm) = 3.24 L, which is closest to choice C.

What Volume Does 40