How many grams of NaOH are contained in 5.0 $\times$ 10² mL of a 0.74 M sodium hydroxide solution?

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Quizplus · Accepted Answer

The correct answer is A because the number of moles of NaOH in 5.0 x 10^2 mL of a 0.74 M solution is:Moles of NaOH = Molarity x Volume (in liters)Moles of NaOH = 0.74 M x 0.500 LMoles of NaOH = 0.37 molesThe mass of NaOH in grams is:Mass of NaOH = Moles of NaOH x Molar mass of NaOHMass of NaOH = 0.37 moles x 40.00 g/molMass of NaOH = 15 g

How Many Grams of NaOH Are Contained in 5 ×\times× 102 ML of a 0

How Many Grams of NaOH Are Contained in 5 $\times$ 10² ML of a 0