Consider the following hypothetical reaction at 310 K.Standard free energies of formation are given in parentheses. B $\to$C
$\Delta$G° = -32.6 kJ/mol(?)
(176.4 kJ/mol)
Calculate the standard free energy of formation of compound B.

Question

Quizplus · Accepted Answer

By using the equation ΔG°= ΣnΔG°f(products) - ΣnΔG°f(reactants), we can solve for the standard free energy of formation of compound B:

ΔG° = -32.6 kJ/mol - 3(0 kJ/mol) + ΔG°f(B)
ΔG° = ΔG°f(B) - 32.6 kJ/mol
ΔG°f(B) = ΔG° + 32.6 kJ/mol
ΔG°f(B) = -143.8 kJ/mol + 32.6 kJ/mol
ΔG°f(B) = -111.2 kJ/mol

Therefore, the standard free energy of formation of compound B is -111.2 kJ/mol, which corresponds to choice A (-209.0 kJ/mol is the free energy of formation for compound C).

Consider the Following Hypothetical Reaction at 310 K →\to→ C Δ\DeltaΔ G° = -326 KJ/mol(?) (176

Consider the Following Hypothetical Reaction at 310 K $\to$ C $\Delta$ G° = -326 KJ/mol(?)
(176