In a solution prepared by adding excess PbI 2 (K sp = 1.44 $\times$ 10 - 8 )to water,the [I - ] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L

The Answer of In a solution prepared by adding excess PbI 2 (K sp = 1.44 $\times$ 10 - 8 )to water,the [I - ] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L

In a solution prepared by adding excess PbI 2 (K sp = 1.44 $\times$ 10 - 8 )to water,the [I - ] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L

The Answer of In a solution prepared by adding excess PbI 2 (K sp = 1.44 $\times$ 10 - 8 )to water,the [I - ] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L

Solved

In a Solution Prepared by Adding Excess PbI₂ (K_sp = $\times$

Question 36

Multiple Choice

In a solution prepared by adding excess PbI₂ (K_sp = 1.44 $\times$ 10^-⁸) to water,the [I^-] at equilibrium is:

A) $In a solution prepared by adding excess PbI2 (Ksp = 1.44 \times 10-8) to water,the [I-] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L$ mol/L
B) $In a solution prepared by adding excess PbI2 (Ksp = 1.44 \times 10-8) to water,the [I-] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L$ mol/L
C) $In a solution prepared by adding excess PbI2 (Ksp = 1.44 \times 10-8) to water,the [I-] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L$ mol/L
D) $In a solution prepared by adding excess PbI2 (Ksp = 1.44 \times 10-8) to water,the [I-] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L$ mol/L
E) $In a solution prepared by adding excess PbI2 (Ksp = 1.44 \times 10-8) to water,the [I-] at equilibrium is: A) mol/L B) mol/L C) mol/L D) mol/L E) mol/L$ mol/L