The overall K_f for the complex ion Ag(NH₃)₂⁺ is 1.7 $\times$10⁷.The K_sp for AgI is 1.5 $\times$ 10^-¹⁶.What is the molar solubility of AgI in a solution that is 2.0 M in NH₃? A)1.5 $\times$ 10^-⁹ B)1.3 $\times$ 10^-³ C)1.0 $\times$ 10^-⁴ D)5.8 $\times$ 10^-¹² E)8.4 $\times$ 10^-⁵

Question

Quizplus · Accepted Answer

The molar solubility of AgI in the presence of NH3 can be calculated using the formula: S = sqrt(Ksp / (Kf * [NH3]^2)). Substituting the given values, S = sqrt(1.5 x 10^-16 / (1.7 x 10^7 * (2.0)^2)) = 1.0 x 10^-4 M.

The Overall Kf for the Complex Ion Ag(NH3)2+ Is 1 ×\times×

The Overall K_f for the Complex Ion Ag(NH₃)₂⁺ Is 1 $\times$