What is the molarity of a sodium hydroxide solution if 28.7 mL of this solution reacts exactly with 22.30 mL of 0.253 M sulfuric acid?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is: 2 NaOH + H2SO4 → Na2SO4 + 2 H2O. This shows that 2 moles of NaOH react with 1 mole of H2SO4. First, calculate the moles of H2SO4: 0.02230 L * 0.253 mol/L = 0.0056419 mol. Since the ratio is 2:1, the moles of NaOH needed are 2 * 0.0056419 = 0.0112838 mol. The molarity of NaOH is then 0.0112838 mol / 0.0287 L = 0.393 M.

What Is the Molarity of a Sodium Hydroxide Solution If