A 50.00-mL solution of 0.0350 M aniline (K_b = 3.8 $\times$10^-¹⁰)is titrated with a 0.0127 M solution of hydrochloric acid as the titrant.What is the pH at the equivalence point? (K_w = 1.0 $\times$10^-¹⁴)

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The Answer of A 50.00-mL solution of 0.0350 M aniline (K_b = 3.8 $\times$10^-¹⁰)is titrated with a 0.0127 M solution of hydrochloric acid as the titrant.What is the pH at the equivalence point? (K_w = 1.0 $\times$10^-¹⁴)

A 5000-ML Solution of 0 ×\times× 10-10)is Titrated with a 0 ×\times×

A 5000-ML Solution of 0 $\times$ 10^-¹⁰)is Titrated with a 0 $\times$