Nitrogen gas (N₂)reacts with hydrogen gas (H₂)to form ammonia (NH₃).At 200°C in a closed container,1.0 atm of nitrogen gas is mixed with 2.0 atm of hydrogen gas.At equilibrium,the total pressure is 2.2 atm.Calculate the partial pressure of hydrogen gas at equilibrium.

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:

N2 + 3H2 → 2NH3

According to the stoichiometry of the reaction, for every 1 mole of nitrogen gas consumed, 3 moles of hydrogen gas are also consumed. Therefore, we can use the ideal gas law to set up an expression relating the partial pressure of hydrogen gas to that of nitrogen gas:

(Ptotal - P(H2)) / P(N2) = 3/1

where Ptotal is the total pressure at equilibrium. Plugging in the given values, we get:

(2.2 atm - P(H2)) / 1.0 atm = 3/1

Solving for P(H2), we get:

P(H2) = 0.8 atm

Therefore, the partial pressure of hydrogen gas at equilibrium is 0.8 atm, which corresponds to choice B.

Nitrogen Gas (N2)reacts with Hydrogen Gas (H2)to Form Ammonia (NH3)

Nitrogen Gas (N₂)reacts with Hydrogen Gas (H₂)to Form Ammonia (NH₃)