Carbon disulfide and chlorine react according to the following equation: CS₂(g) + 3Cl₂(g) S₂Cl₂(g) + CCl₄(g)
When 2.14 mol of CS₂ and 5.85 mol of Cl₂ are placed in a 2.00-L container and allowed to come to equilibrium,the mixture is found to contain 0.620 mol of CCl₄.How many moles of Cl₂ are present at equilibrium?

Question

Carbon disulfide and chlorine react according to the following equation: CS₂(g) + 3Cl₂(g)

Carbon disulfide and chlorine react according to the following equation: CS<sub>2</sub>(g) + 3Cl<sub>2</sub>(g) S<sub>2</sub>Cl<sub>2</sub>(g) + CCl<sub>4</sub>(g) When 2.14 mol of CS<sub>2</sub> and 5.85 mol of Cl<sub>2</sub> are placed in a 2.00-L container and allowed to come to equilibrium,the mixture is found to contain 0.620 mol of CCl<sub>4</sub>.How many moles of Cl<sub>2</sub> are present at equilibrium? A) 1.520 mol B) 0.620 mol C) 3.99 mol D) 4.61 mol E) 2.00 mol

S₂Cl₂(g) + CCl₄(g)
When 2.14 mol of CS₂ and 5.85 mol of Cl₂ are placed in a 2.00-L container and allowed to come to equilibrium,the mixture is found to contain 0.620 mol of CCl₄.How many moles of Cl₂ are present at equilibrium?

Quizplus · Accepted Answer

The Answer of Carbon disulfide and chlorine react according to the following equation: CS₂(g)+ 3Cl₂(g) S₂Cl₂(g)+ CCl₄(g) When 2.14 mol of CS₂ and 5.85 mol of Cl₂ are placed in a 2.00-L container and allowed to come to equilibrium,the mixture is found to contain 0.620 mol of CCl₄.How many moles of Cl₂ are present at equilibrium?

Carbon Disulfide and Chlorine React According to the Following Equation