At a given temperature,a first-order reaction has a rate constant of 3.4 $\times$ 10^-³ s^-¹.The time required for the reaction to be 44% completed is

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For a first-order reaction, the time required for a certain percentage of completion can be calculated using the formula $t = \frac{\ln(\frac{100}{100-x})}{k}$, where $x$ is the percentage of completion and $k$ is the rate constant. Given that the reaction is 44% completed, $x = 44$, and the rate constant $k = 3.4 \times 10^{-3} s^{-1}$. Converting the rate constant to minutes ($1 min = 60 s$), we get $k = 3.4 \times 10^{-3} \times 60 min^{-1}$. Plugging the values into the formula gives $t \approx 2.8$ minutes.

At a Given Temperature,a First-Order Reaction Has a Rate Constant ×\times×

At a Given Temperature,a First-Order Reaction Has a Rate Constant $\times$