The experimental rate law for the decomposition of nitrous oxide (N2O) to N2 and O2 is Rate = k[N2O]2.Two mechanisms are proposed:
I.N2O N2 + O
N2O + O N2 + O2
II.2N2O
N4O2
N4O2 2N2 + O2
Which of the following could be a correct mechanism?
A) Mechanism I,with the first step as the rate-determining step.
B) Mechanism I,with the second step as the rate-determining step as long as the first step is a fast equilibrium step.
C) Mechanism II,with the second step as the rate-determining step if the first step is a fast equilibrium step.
D) None of the choices (A-C) could be correct.
E) At least two of the above choices (A-C) could be correct.
Correct Answer:
Verified
Q59: A first-order reaction is 40.0% complete
Q60: Consider the reaction 3A + B
Q61: Two isomers (A and B)of a
Q62: The rate law for a reaction
Q63: A particular first-order reaction has a rate
Q65: The radioactive nuclide Q66: Determine the molecularity of the following Q67: Of what use is it to find Q68: The reaction A Q69: The reaction A ![]()
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents