The average electrical current delivered if 1.0 g of zinc were oxidized to zinc(II) in 60 s is ________

Question

Quizplus · Accepted Answer

To find the average current, use the formula I = Q/t, where Q is the charge and t is the time. First, calculate the moles of zinc: 1.0 g Zn / 65.38 g/mol = 0.0153 mol. Since zinc is oxidized to Zn²⁺, it loses 2 moles of electrons per mole of zinc: 0.0153 mol Zn × 2 mol e⁻/mol Zn = 0.0306 mol e⁻. The charge Q is then 0.0306 mol e⁻ × 96485 C/mol e⁻ = 2953.5 C. Finally, the average current is I = 2953.5 C / 60 s = 49.2 A.

The Average Electrical Current Delivered If 1 ×\times× 10-2 A ×\times× 10-2 A

The Average Electrical Current Delivered If 1 $\times$ 10^-2 A $\times$ 10^-2 A