The standard molar entropy of magnesium fluoride (MgF₂) is 57.2 J/(mol . K). What is the entropy of 4.75 g of MgF₂? A)(+4.36 J/K) B)(-4.36 J/K) C)(+272 J/K) D)(-272 J/K) E)0 J/K

Question

Quizplus · Accepted Answer

To find the entropy of 4.75 g of MgF2, first calculate the moles of MgF2 using its molar mass (approximately 62.3 g/mol for MgF2). Moles = 4.75 g / 62.3 g/mol ≈ 0.0762 mol. Then, multiply the moles by the standard molar entropy (57.2 J/(mol·K)): 0.0762 mol * 57.2 J/(mol·K) ≈ 4.36 J/K.

The Standard Molar Entropy of Magnesium Fluoride (MgF2) Is 57

The Standard Molar Entropy of Magnesium Fluoride (MgF₂) Is 57