Hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water. If $\Delta$H $\circ$ = -56.13 kJ/mol and $\Delta$S $\circ$ = 79.11 J/mol . K, what is the temperature (in $\circ$ C) of the reaction if $\Delta$G $\circ$ = - 80.89 kJ/mol?

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The Answer of Hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCl) and water. If $\Delta$H $\circ$ = -56.13 kJ/mol and $\Delta$S $\circ$ = 79.11 J/mol . K, what is the temperature (in $\circ$ C) of the reaction if $\Delta$G $\circ$ = - 80.89 kJ/mol?

Hydrochloric Acid (HCl) Reacts with Sodium Hydroxide (NaOH) to Form Δ\DeltaΔ

Hydrochloric Acid (HCl) Reacts with Sodium Hydroxide (NaOH) to Form $\Delta$