The pH of an ammonia solution is 11.6, and the solution has a concentration of about 0.20 M. The pK_b of ammonia is 4.75. What is the percent ionization of ammonia?

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Quizplus · Accepted Answer

The percent ionization of ammonia can be calculated using the following equation:% ionization = [NH4+]/[NH3] * 100%where [NH4+] is the concentration of ammonium ions and [NH3] is the concentration of ammonia.The concentration of ammonium ions can be calculated using the following equation:[NH4+] = Kw/[OH-]where Kw is the ion product constant for water (1.0 x 10^-14) and [OH-] is the concentration of hydroxide ions.The concentration of hydroxide ions can be calculated using the following equation:[OH-] = 10^-pHwhere pH is the pH of the solution.Substituting the given values into these equations, we get:[NH4+] = 1.0 x 10^-14/[10^-11.6] = 2.0 x 10^-3 M[NH3] = 0.20 M% ionization = (2.0 x 10^-3 M)/(0.20 M) * 100% = 1.0%Therefore, the percent ionization of ammonia is 1.0%.

The PH of an Ammonia Solution Is 11