Solved

The Equilibrium Constant for the Acid Ionization of Mercaptoethanol (HSCH2CH2OH ×\times

Question 38

Multiple Choice

The equilibrium constant for the acid ionization of mercaptoethanol (HSCH2CH2OH ) is 1.91 ×\times 10-10. HSCH2CH2OH(aq)  The equilibrium constant for the acid ionization of mercaptoethanol (HSCH<sub>2</sub>CH<sub>2</sub>OH )  is 1.91  \times  10<sup>-10</sup><sub>.</sub> <sub> </sub><sub> </sub>HSCH<sub>2</sub>CH<sub>2</sub>OH(aq)    H<sup>-</sup>(aq)  + SCH<sub>2</sub>CH<sub>2</sub>OH<sup>-</sup>(aq)  Which of the following is true regarding this equilibrium? I.The reaction is product-favored. II.The reaction is reactant-favored. III.Equilibrium lies far to the right. IV.Equilibrium lies far to the left. A) I and III B) I and IV C) II and III D) II and IV E) None are true, as the concentrations of reactants and products are comparable. H-(aq) + SCH2CH2OH-(aq)
Which of the following is true regarding this equilibrium?
I.The reaction is product-favored.
II.The reaction is reactant-favored.
III.Equilibrium lies far to the right.
IV.Equilibrium lies far to the left.


A) I and III
B) I and IV
C) II and III
D) II and IV
E) None are true, as the concentrations of reactants and products are comparable.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents